Most current solutions will fail if the four points fall on a circle but don't form a rectangle. Try adding X=[0 sqrt(2)/2 sqrt(2)/2 0]', Y=[1 sqrt(2)/2 -sqrt(2)/2 -1]'
Jon, I updated the test suite to include parallelograms that are not rectangles. While it does not include the specific example you gave, I think it takes care of the problem. Let me know if you think there is still an issue.
Matt, Jon's example can 'kill' some approaches, that check for trapezoids. X=[-1 -0.5 0.5 1]; Y=[0 sqrt(3)/2 sqrt(3)/2 0]; can eliminate those solutions which check only for 3 unique distances between points. It would be beneficial, to try some trapezoids, as well as kites or rhombi. Anyway, great problem!
Ah yes, I agree. Test suite updated again.
Time to work on plan B; pdist isn't valid in Cody. :-(
This one should not pass, it checks for parallelograms.
Thanks for bringing this to my attention Jan. Test suite has been updated.
Sort a list of complex numbers based on far they are from the origin.
How to find the position of an element in a vector without using the find function
Whether the input is vector?
The sum of the numbers in the vector
04 - Scalar Equations 2
Create cell array of numeric arrays
Convert matrix to 3D array of triangular matrices
SET (the card game)
Determine the number of maximal cliques in an undirected graph
Maximum of each diagonal
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office