2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2^N?
Thanks to Project Euler Problem 16.
added a test case to make it a wee bit harder
function y = pow2_sumofdigits(x)
number = sym(2^x);
n = char(number);
y = 0;
for i = 1:length(n)
y = y + str2double(n(i));
this code gives exact results on my mechine but not work in cody show error
Error: License checkout failed.
License Manager Error -5
Cannot find a license for Symbolic_Toolbox.
Troubleshoot this issue by visiting:
License path: email@example.com:firstname.lastname@example.org:/tmp/matlabpref/.matlab/R2013a_licenses:/opt/mlsedu/matlab/R2013a/licenses/license.dat:/opt/mlsedu/matlab/R2013a/licenses
Licensing error: -5,0.
please help me ...........
Replace May with April
Getting the indices from a vector
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Pull the variable y_correct from the Caller's Workspace
Next Lower Power of B
THE CALCULATOR OF LOVE
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