If x=[0,3,4,2,1] then y=[4,3,2,1,0]
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it is a good problem,but I cann't solve it
Only one verification test!? and this test already has the vector sorted.
li look up the options of the sort command
Needs (much) more tests in the Test Suite!! It would also be a good idea to include a randomly generated vector in the tests; for this random input, testing of the correct function output should be hard-coded as: assert(y(1)>=y(2)); assert(y(2)>=y(3)); ... ; assert(y(end-1)>=y(end)); [It's not the most efficient check, but anything else will risk giving away clues on possible solution codes.]
i comment for the challenge
nice
comment = badge
I do not understand what is wrong with the solution?
I solved question with my algorithm
function y=desSort(x)
x=input(' give me input to obtain descending order of input')
y = zeros(size(x));
indis=0;
for j=1:length(x)
maksimum=x(j);
for i=1:length(x)
if x(i)>maksimum
maksimum=x(i);
a=i;
end
end
x(a)= 0
y(j)=maksimum
end
end
sort
tried using the sort function in a descending order would not work
good
sort with direction
good question
Good problem
interesting