Create the convolution-power vector from initial vector x and power n. In other words, similar to the scalar case, raising to the n-th power means repeating the convolution on itself n times.
Assume that n is a non-negative integer and x is a row vector.
Examples:
convpower(1:5,0)
ans =
1 convpower(1:5,1)
ans =
1 2 3 4 5 convpower(1:5,2)
ans =
1 4 10 20 35 44 46 40 25Neither string operations nor interpolations are allowed!
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Unfortunately the FFT based solution using a binary expansion of 'n' won't be Cody-optimal :-)