This Challenge is to solve Question A of the USC ACM Fall 2012 Contest.
Given an array M of Valid binary codewords(m codewords of width n) and a Received Corrupted(?) codeword of width n, determine the minimum number of flipped bits in the Received codeword to generate a valid codeword.
Input: [ M, v ]
Output: e, minimum number of error(flipped) bits .
From full USC data file
Input: [0 0 0; 1 1 1; 1 1 0], [0 1 0]
Output: 1 as [0 1 0] can convert to [0 0 0] or [1 1 0] with a single flip
Matlab one-liner?
The Winning C solution - not much help:
#include <iostream>
#include <stdio.h>
#include <string>
using namespace std;
int main () {
freopen("codes.in", "r", stdin);
int K,n,b;
cin >> K;
for (int i = 1; i < K + 1; ++i) {
cin >> n >> b;
string m[1000], r;
for (int j = 0; j < n; ++j)
cin >> m[j];
cin >> r;
% Process Start
int f = b;
for (int j = 0; j < n; ++j) {
int d = b;
for (int k = 0; k < b; ++k) {
if (m[j][k] == r[k])
--d;
}
f = ((f <= d) ? f : d);
}
% Process End
printf("Data Set %d:\n", i);
printf("%d\n\n", f);
}
return 0;
}
Solution Stats
Solution Comments
Show commentsProblem Recent Solvers19
Suggested Problems
-
Return the 3n+1 sequence for n
8491 Solvers
-
94 Solvers
-
Sum all integers from 1 to 2^n
17456 Solvers
-
Make an awesome ramp for a tiny motorcycle stuntman
750 Solvers
-
Side of an equilateral triangle
6883 Solvers
More from this Author308
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!