i want to assign number of tasks to fog nodes randomly son in the matrix i will have different solution and i got the same solution repeated

lb=250;
ub= 1000;
dim = 5;
pop=5;
offloading =  lb + (ub - lb) .* rand(1,dim); 
         %Initialization
         
    fognodesnumber = 3;     
for i = 1 : pop  %pop=N, population size
         
 for task = 1 : dim 
     indices = randperm(length(offloading)); 
         indices2 = randperm(fognodesnumber); 
  for FN=1:fognodesnumber
    x(task,indices2(FN))=offloading(indices(task));
    % Evaluate the fitness of the new solution
    fit(task,FN)=fobj(x(task,indices2(FN)));
  
  end
 end
end

so the reult i got for x is

x =
  357.1360  357.1360  357.1360
  520.0463  520.0463  520.0463
  370.7144  370.7144  370.7144
  370.7144  370.7144  370.7144
  663.3892  663.3892  663.3892

but i need each column the numbers to be distributed differently

Answer 1

[Shravan Kumar Vankaramoni]

Hi,

for FN=1:fognodesnumber
    x(task,indices2(FN))=offloading(indices(task));
end

In the above loop, task( row number ) is a constant value. Basically you are storing same value in the entire row. To get different values in the columns of the same row, you can try the below code. It is randomizing the value to be stored.

for FN=1:fognodesnumber
    x(task,indices2(FN))=offloading(indices(randi([1,dim])));
end

[maria alseid]