sub divide the image with overlaps

my image is a =

      [0     0     1     1;
       0     0     1     1;
       0     2     2     2;
       2     2     3     3];(this is only example image actual image is larger than this) i want to sub divide this into 4*4 blocks with overlaps.then i want to call each individual nine blocks.(B1,B2,........,B9);

B(1,1)=[0 0;0 0];
B(1,2)=[0 1;0 1];
B(1,3)=[1 1;1 1];
B(2,1)=[0 0;0 2];
B(2,2)=[0 1;2 2];how can i do this.

[mahesh chathuranga]

is there any method to subdivide the image with overlaps?

Answer 1

[Image Analyst]

I don't know what you mean when you say "i want to call each individual nine blocks". Perhaps blockproc() can work for you, or simply conv2() . Or maybe mat2cell() . Depends on what "call" means. See the FAQ: http://matlab.wikia.com/wiki/FAQ#How_do_I_split_an_image_into_non-overlapping_blocks.3F if you want non-overlapping blocks. You can have blockproc() to overlapping blocks instead of moving over in jumps but it's a little non-obvious. Or you can use imfilter() or nlfilter() if you have the Image Processing Toolbox.

[mahesh chathuranga]

call means ,i want to display each blocks separately and i want to do some calculations for each block.i want to address each block. yes you are correct i have tried for blkproc. can i apply more than one function as fun in

B = blkproc(A,[m n],[mborder nborder],fun).

[Image Analyst]

See the attached demos. You can run a custom function in blockproc() (this is in the demo) and in there you can use imshow() to display the small individual blocks if you want.