Confusion on function handles

Greetings,
I know this is a tricky subject for me to understand, but I want to see if I'm going about this right.
I have the following three functions:
f(x)= x^8 + 8*x^7 + 28*x^6 + 56*x^5 +70*x^4 - 56*x^3 + 28*x^2 - 8*x +1
g(x)=(((((((x-8)*x + 28) - 56)*x + 70) - 56)*x + 28)*x - 8)*x + 1
h(x)=(x-1)^8
that need to be evaluated at 101 equally spaced points in the interval [0.99,1.01] and plot the results on the magnified scale.
Now, can I use function handles with this, i.e. (as a start),
f =@(x) x^8 + 8*x^7 + 28*x^6 + 56*x^5 +70*x^4 - 56*x^3 + 28*x^2 - 8*x +1
g =@(x) (((((((x-8)*x + 28) - 56)*x + 70) - 56)*x + 28)*x - 8)*x + 1
h =@(x) (x-1)^8
n = 100;
a = 0.99;
b = 1.01;
t = a:(b-a)/n:b;
Or am I way off?
Thanks!

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Jesse, if you want to add a comment click on [comment on this answer]

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Answers (2)

Shashank Prasanna
Shashank Prasanna on 26 Sep 2013
Edited: Shashank Prasanna on 26 Sep 2013
You need to precede your operations with a dot "." as described here:
Then create your anonymous function handles.
Create linearly spaced points using LINSPACE:
x = linspace(0.99,1.01,100);
Call the function with x as input

2 Comments

Jesse commented
Shashank,
Thanks for the response. Forgot about the dots! So, like this?
f =@(x) x.^8 + 8*x.^7 + 28*x.^6 + 56*x.^5 +70*x.^4 - 56*x.^3 + 28*x.^2 - 8*x +1 g =@(x) (((((((x-8)*x + 28) - 56)*x + 70) - 56)*x + 28)*x - 8)*x + 1 h =@(x) (x-1).^8
x = linspace(0.99,1.01,100);
Shouldn't the 100 be 101 for 101 equally spaced points?
So how is the call made in this fashion?
Thanks again!
Jesse, here is an example, you can follow the same approach for any anonymous function handles that has been defined the proper way to do elementwise operations:
h =@(x) (x-1).^8;
x = linspace(0.99,1.01,100);
plot(x,h(x))

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for k=1:numel(t)
y(k)=f(t(k))+g(t(k))+h(t(k))
end
plot(t,y)

1 Comment

Jesse commented
Azzi,
I take it I still need the dots to definte t(k)? How is t(k) defined? Thanks!

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Asked:

on 26 Sep 2013

Commented:

on 27 Sep 2013

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