# Need to Produce a different matrix after each loop

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DARLINGTON ETAJE on 25 Jun 2021
Hello Friends,
I need to produce a different set of deli after each loop but it remains the same. Help me out please...see code below.
deli is suppose to be different set of 12 by 1 after each loop
L1=[1 33 34 2 35 36 3 37 38 4 39 40];
L2=[3 37 38 4 39 40 5 41 42 6 43 44];
L3=[5 41 42 6 43 44 7 45 46 8 47 48];
L4=[7 45 46 8 47 48 9 49 50 10 51 52];
L5=[9 49 50 10 51 52 11 53 54 12 55 56];
L6=[11 53 54 12 55 56 13 57 58 14 59 60];
L7=[13 57 58 14 59 60 15 61 62 16 63 64];
L8=[15 61 62 16 63 64 17 65 66 18 67 68];
L9=[17 65 66 18 67 68 19 69 70 20 71 72];
L10=[19 69 70 20 71 72 21 22 23 24 25 26];
L11=[21 22 23 24 25 26 27 28 29 30 31 32];
L=[L1;L2;L3;L4;L5;L6;L7;L8;L9;L10;L11];
delu=[-107.9277784;-473.7489066;-456.4464814;-298.1506906;-38.38102414;169.6616599;218.8447121;105.0260144;-78.47051372;-205.707;-1.1961463;701.7499816;-2084.55571;-1229.851404;-0.390010302;39.67805573;-68.88297022;2231.216584;-5473.430599;-3189.887351;-0.390010302;41.85037402;-72.64553587];
delr=zeros(49,1);
del=[delu;delr];
deli=zeros(12,1);
delbar=([]);
mbar=repmat({zeros(12,1)},n,1);
for i=1:n
for p=1:12
deli(p,1)=del((L(i,p)),1);
end
mbar{i}=(kg{i}*deli)+fembar{i};
end
DARLINGTON ETAJE on 28 Jun 2021
Thank you so much.

Jayant Gangwar on 7 Jul 2021
It is my understanding that you want to produce and store the set of deli after each iteration. In your current code the deli produced after each set is correct you just need to store it as well after each iteration. In the code below each column of delstore represents the set of deli after the corresponding iteration.
L1=[1 33 34 2 35 36 3 37 38 4 39 40];
L2=[3 37 38 4 39 40 5 41 42 6 43 44];
L3=[5 41 42 6 43 44 7 45 46 8 47 48];
L4=[7 45 46 8 47 48 9 49 50 10 51 52];
L5=[9 49 50 10 51 52 11 53 54 12 55 56];
L6=[11 53 54 12 55 56 13 57 58 14 59 60];
L7=[13 57 58 14 59 60 15 61 62 16 63 64];
L8=[15 61 62 16 63 64 17 65 66 18 67 68];
L9=[17 65 66 18 67 68 19 69 70 20 71 72];
L10=[19 69 70 20 71 72 21 22 23 24 25 26];
L11=[21 22 23 24 25 26 27 28 29 30 31 32];
L=[L1;L2;L3;L4;L5;L6;L7;L8;L9;L10;L11];
delu=[-107.9277784;-473.7489066;-456.4464814;-298.1506906;-38.38102414;169.6616599;218.8447121;105.0260144;-78.47051372;-205.707;-1.1961463;701.7499816;-2084.55571;-1229.851404;-0.390010302;39.67805573;-68.88297022;2231.216584;-5473.430599;-3189.887351;-0.390010302;41.85037402;-72.64553587];
delr=zeros(49,1);
del=[delu;delr];
deli=zeros(12,1);
delbar=([]);
delstore=[];
n = 2; kg = {3;5}; fembar = {2; 103};
mbar=repmat({zeros(12,1)},n,1);
for i=1:n
for p=1:12
deli(p,1)=del((L(i,p)),1);
end
delstore=[delstore,deli];
mbar{i}=(kg{i}*deli)+fembar{i};
end
DARLINGTON ETAJE on 7 Jul 2021
Thank you