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Could anyone help me how to simplify the following code.

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jaah navi
jaah navi on 23 Jun 2021
Commented: jaah navi on 23 Jun 2021
A = cell(1,15)
B=A'
B{1}=cell(2,1)
B{2}=cell(2,1)
B{3}=cell(2,1)
B{4}=cell(2,1)
B{5}=cell(2,1)
B{6} = cell(2,2)
B{7}= cell(2,2)
B{8} = cell(2,2)
B{9}= cell(2,2)
B{10} = cell(2,2)
B{11}= cell(2,3)
B{12}= cell(2,3)
B{13}= cell(2,3)
B{14}= cell(2,3)
B{15}= cell(2,3)
in this code instead to write each and every row of the cell array separately is there any method that could be done to simplify it in the single step. For example B{1}.......B{5} are of the same size(2,1) ,B{6}.......B{10} of (2,2) , B{11}.....B{15} of (2,3) .IS it possible to write all the lines in a single step.
  1 Comment
KSSV
KSSV on 23 Jun 2021
Why you are bothered to initialize a cell in each cell in an cell array? You are missing something here.

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Accepted Answer

Mohammad Sami
Mohammad Sami on 23 Jun 2021
I am not sure why you are creating a nested cell array. However you can do it like this.
B = arrayfun(@(x,y)cell(x,y),ones(15,1)*2,repelem([1:3]',5,1),'UniformOutput',false)
B = 15×1 cell array
{2×1 cell} {2×1 cell} {2×1 cell} {2×1 cell} {2×1 cell} {2×2 cell} {2×2 cell} {2×2 cell} {2×2 cell} {2×2 cell} {2×3 cell} {2×3 cell} {2×3 cell} {2×3 cell} {2×3 cell}
  4 Comments
jaah navi
jaah navi on 23 Jun 2021
I need another help from you.
could you please help me to create categorical array for B = 15×1 cell array
{2×1 cell}
{2×1 cell}
{2×1 cell}
{2×1 cell}
{2×1 cell}
{2×2 cell}
{2×2 cell}
{2×2 cell}
{2×2 cell}
{2×2 cell}
{2×3 cell}
{2×3 cell}
{2×3 cell}
{2×3 cell}
{2×3 cell}

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