Plotting acceleration vs time on Matlab from accelerometer data that doesn't have a time column
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Hello, I would like to plot x y and z axes of acceleration versus time from the csv file that was outputted from my sensor, the first two rows of the data of the csv file give the timestamp and the frequency of the reading therefore they should not be read by matlab and the columns represent x y and z axes respectively. The problem I am having is that the file does not have a time column and that I need to create an abstract one so that I could plot the acceleration vs time (or do I actually need one? is there a command that I can just use?) Thank you very much in advance!!
3 Comments
David Hill
on 7 Jun 2021
You need to convert the time stamps into time. What is the format of the time stamp?
Adviye Irem Yuceel
on 7 Jun 2021
Adviye Irem Yuceel
on 7 Jun 2021
Answers (2)
Mathieu NOE
on 8 Jun 2021
hello
as we know the sampling rate Fs and the amount of samples , there is no big difficulty to reconstruct a time vector :
samples = length(data);
dt = 1/Fs;
time_vector = (0:samples-1)*dt
Duncan Po
on 8 Jun 2021
0 votes
You can create a timetable, and just supply the start time and frequency. Timetable will compute the timestamps for your data. For example,
>> data = (1:10)';
>> starttime = datetime('now');
>> fs = 2; % 2Hz in this example
>> tt = timetable(data, 'StartTime', starttime, 'SampleRate', fs)
tt =
10×1 timetable
Time data
____________________ ____
08-Jun-2021 14:59:30 1
08-Jun-2021 14:59:30 2
08-Jun-2021 14:59:31 3
08-Jun-2021 14:59:31 4
08-Jun-2021 14:59:32 5
08-Jun-2021 14:59:32 6
08-Jun-2021 14:59:33 7
08-Jun-2021 14:59:33 8
08-Jun-2021 14:59:34 9
08-Jun-2021 14:59:34 10
You can then either plot directly using stackedplot, or extract the timestamps using tt.Time, and then call plot.
2 Comments
Adviye Irem Yuceel
on 8 Jun 2021
Duncan Po
on 9 Jun 2021
To plot the timetable using stackedplot, you can simply pass in the timetable as the only input:
stackedplot(tt)
The error you encountered is due to the second input y. Apparently y is not a valid second input.
For unix time, there is a way to convert using the datetime function:
starttime = datetime(t, 'ConvertFrom','posixTime');
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