Given an integer number n (0<=n<10000), write a code returning the difference between the product of its digits and the sum of its digits.

Given an integer number n (0<=n<10000), write a code returning the difference between the product of its digits and the sum of its digits. For instance, if n=432 then the result is 4*3*2-(4+3+2) = 15.

[Walter Roberson]

hints: https://www.mathworks.com/matlabcentral/answers/391891-find-numbers-whose-product-of-digits-is-6-times-the-sum-of-the-digits?s_tid=srchtitle

Answer 1

[SALAH ALRABEEI]

    % check this
a = 4321;
b=str2num(num2str(a)');
diff = abs(sum(b)- prod(b))

[Walter Roberson]

we do not encourage giving full solutions for homework, especially when the person has not made any attempts to solve the problem. Posting a homework question without even any discussion tends to suggest that the person is not interested in anything other than copying the solution without any work.

[haneen yousef]

this is not what i am doing , i already have my solution which i can copy and paste it here if you like , i had a little difficuilty doing it so i wanted to make sure if my soultion is correct or no

You can check if you want !

str=input('enter a number');
X = 0;
Y = 1;
W = str;
while W
 digit = mod(W, 10);
 X = X + digit;
 Y = Y * digit;
 W = fix(W/10);
end
answer = Y - X;
disp(answer)

[SALAH ALRABEEI]

totally agree. Noted.

[Walter Roberson]

@haneen yousef

That code seems to work when I test, except for 0 exactly.

For 0 exactly your Y would be 1 and your X would be 0 so you would get 1-0 = 1 as your solution, but for 0 exactly the product of the digits should be 0.