Is there a more efficient way to compute this other than using a loop ?

Hello,

Say, vectors a and b have different sizes. I wonder if there is a simpler and more efficient way of writing the lines below.

b = [1 3 4 7 8 10 2 5 6];
a = [2 3 9];
for ii = 1:length(a)
    b(b==a(ii))=[];
end

Output:

b = 1	4	7	8	10	5	6

Thanks!

Answer 1

[Matt J]

b=setdiff(b,a,'stable')

[Rayan Glus]

Thank you so much, Matt.