Find in a cell array?

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M G
M G on 7 Aug 2013
Commented: Marwan Malaeb on 20 May 2022
Hello all,
Suppose a cell array 10x1 consisted of random numbers from 1 to 5. How can I find the locations for number 5?
All the best,
MhD
  3 Comments
Marwan Malaeb
Marwan Malaeb on 20 May 2022
call this array for example X
type k=find(X==5)
it will return for you the number of the cell that has the value of 5.

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Accepted Answer

Jan
Jan on 7 Aug 2013
Edited: Jan on 7 Aug 2013
C = {1,5,3,4,2,3,4,5,2,1};
index = find([C{:}] == 5);
Here [C{:}] is a faster inlined version of cell2mat.
Alternative:
index = cellfun(@(x) x==5, C, 'UniformOutput', 1);
Or the long and most likely faster form:
index = false(1, numel(C))
for k = 1:numel(C)
index(k) = (C{k} == 5);
end
[EDITED] If you are talking of a cell string, this is much faster:
D = {'1' '5' '3' '4' '2' '3' '4' '5' '2' '1'};
index = find(strcmp(D, '5'));
  5 Comments
Kylie Hansen
Kylie Hansen on 16 Aug 2017
Just a casual MATLAB coder dropping by this older thread on a hunt for answers. Your response for the cell string method worked easily for me. Thank you so much for including it!

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More Answers (2)

Bill Tubbs
Bill Tubbs on 15 Feb 2022
Just in case someone comes here looking to do this with a cell array of chars as I was, it's quite easy this way:
my_cell_array = {'a', 'b', 'c'};
i = find(strcmp(my_cell_array, 'b'));
assert(i == 2)
  1 Comment
hongyi xu
hongyi xu on 17 Apr 2022
Genius! Your supplement exactly fits my question.

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Caroline
Caroline on 7 Aug 2013
Edited: Azzi Abdelmalek on 7 Aug 2013
cellarray_new = zeros; %initializing the array
ind = 1; %indices for new array
for j = 1:10
if (cellarray(j) == 5)
cellarray_new(ind) = j;
ind = ind + 1;
end
end
the array cellarray_new will contain all the indices of the original cell array that contain the number 5
  3 Comments
Filza Ashraf
Filza Ashraf on 22 May 2014
how can i find a pixel intensity if cell contains an image or image is stored in cell???

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