Clear Filters
Clear Filters

lsqcurvefit of a summation function where the parameter to evaluate is the last index of the summation (so an integer)

1 view (last 30 days)
Hi, I'm doing the fit of a function substantially similar to this one: f(x)= sum ( exp(1i * x * jz * c) ) , where: - sum represent the summation over the index jz - x is the variable, - jz = 1,2,...,nz where nz is a parameter to find using the fit, - c is another parameter. The complete function is the product of several series of this type.
In the curve fitting tool I can't enter a summation neither using symsum nor using an iteration. Moreover I can't use nz as a parameter.
Any idea?
Many thanks, Gianluca

Accepted Answer

Oleg Komarov
Oleg Komarov on 30 May 2011
lsqcurvefit is already MIN oof the SUM of euclidean distances of x from y. So, you don't have to use inlcude a sum in your handle and 1:x(2) but:
fh = @(x,xdata) exp(1i.*x(1).*xdata.*x(2)) .* conj(exp(1i.*x(1).*xdata.*x(2)));
  4 Comments
gianluca messina
gianluca messina on 31 May 2011
Sorry, reference in what sense?
I'm fitting an experimental diffraction pattern obtained by xray diffraction from a crystal using the square of an exponential summation (the square because we measure the intensity), and the nz (x(2)) parameter is the number of atomic planes composing the sample
Oleg Komarov
Oleg Komarov on 31 May 2011
I am not sure that you are supplying your problem in the required form, i.e. in lsqcurvefit you can supply a zero ydata and you'll end up with the min wrt nz of SUM{f(.)^2} where the fcn handle is cast in the form I supplied in the body.

Sign in to comment.

More Answers (4)

Walter Roberson
Walter Roberson on 27 May 2011
f = @(x) sum(exp(1i.*c.*x.*(1:nz)))
  1 Comment
gianluca messina
gianluca messina on 27 May 2011
Thanks for your help, but I find this error when I run that function:
Undefined function or method 'isnan' for input arguments of type 'function_handle'.
Gianluca

Sign in to comment.


Arnaud Miege
Arnaud Miege on 27 May 2011
I'm not sure this is something that can be done with the Curve Fitting Toolbox. I think a better approach would be to use the Optimization Toolbox with one of the Least Squares (Curve Fitting) functions, such as lsqcurvefit.
HTH,
Arnaud

gianluca messina
gianluca messina on 30 May 2011
Hi Arnaud, I followed your advice, the problem is that when I calculate the sum both using an iteration and f = @(x,xdata) sum(exp(1i.*x(1).*xdata.*(1:(x(2))))), matlab doesn't recognize that is a function of xdata. So I can't fit it because it sees f and ydata as data of different dimension. Thanks for your help. (And thanks Oleg).
  1 Comment
Oleg Komarov
Oleg Komarov on 30 May 2011
Please post the code snippet you're using (preferably editing this question) and the whole error message. Additional info about the size of your inputs would be beneficial.

Sign in to comment.


gianluca messina
gianluca messina on 30 May 2011
Here is the code:
clear all; close all;
load 'C:\Users\gianluca\Desktop\002Cr-V_Lscan\Cr_MgO_69.txt';
xdata = (Cr_MgO_69(:,1)*2/292.094)'; ydata = (Cr_MgO_69(:,2))';
fh = @(x,xdata) sum(exp(1i.*x(1).*xdata.*(1:x(2)))) .* conj(sum(exp(1i.*x(1).*xdata.*(1:x(2)))));
x0 = [3e-10; 100]; x = lsqcurvefit(fh,x0,xdata,ydata);
and this is the error:
??? Error using ==> lsqncommon at 101 LSQCURVEFIT cannot continue because user supplied objective function failed with the following error: Error using ==> times Matrix dimensions must agree.
Error in ==> lsqcurvefit at 186 [x,Resnorm,FVAL,EXITFLAG,OUTPUT,LAMBDA,JACOB] = ...
Should I try to use an iteration maybe to define the funtion, instead of fh = @(x,xdata)...*(1:x(2))..? I tried but I don't know how to insert x(2) as parameter if it is at the beginning of the for cycle and so before the statement of the funtion:
for jz = 1 : x(2) ... f(jz) = @(x,xdata) ...jz...
end
Yesterday I was using some different code, and I got another error:
??? Error using ==> lsqncommon at 134 Function value and YDATA sizes are incommensurate. (but I think the code I used contained some mistakes)
Many thanks Gianluca

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!