two variables for same coordinate

2 views (last 30 days)
pooja sudha
pooja sudha on 16 May 2021
Commented: pooja sudha on 27 May 2021
Hey,
I have this potential V=1/4*pi*epsilon*sqrt(((r1-r2)^2)+const.^2).
I solved for V =1/4*pi*epsilon*r using finite difference method but I'm unable to understand how to vary two variables for same axis. I have tried to do using different different loop for both parameters but can't find the solutions.
please help

Accepted Answer

Image Analyst
Image Analyst on 16 May 2021
Pooja: You can use either meshgrid() or for loops. Below I show you both ways.
const = 2;
epsilon = 3;
maxR1 = 5.5;
maxR2 = 7.4;
% Define size of output matrix.
rows = 5;
columns = 4;
% Get x and y coordinates at each (y, x) location.
R1 = linspace(1, maxR1, columns); % x
R2 = linspace(1, maxR2, rows); % y
% Method 1 : vectorized using meshgrid()
[r1, r2] = meshgrid(R1, R2)
V = (1/4) * pi * epsilon * sqrt(((r1-r2).^2)+const ^ 2)
% Method 2 : for loops
V = zeros(rows, columns);
for col = 1 : columns
r1 = R1(col);
for row = 1 : rows
r2 = R2(row);
V(row, col) = (1/4) * pi * epsilon * sqrt(((r1-r2).^2)+const ^ 2);
end
end
V
fprintf('Done running %s.m ...\n', mfilename);
  4 Comments
pooja sudha
pooja sudha on 27 May 2021
Hey Thankyou. It worked

Sign in to comment.

More Answers (1)

pooja sudha
pooja sudha on 19 May 2021
please find the attached code.
here i computed for I-dimension & for 1-particle by using the potential V=1/sqrt(r^2+constant^2) ,now same thing I'm trying to do for 2-particle by adding the coordinate for second particle in the potential like V=1/sqrt((r1-r2)^2+constant^2).
please help if you know about this.
Thank you

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!