How to convert radians to degrees?
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Hi, I have this code,
clear all, close all, clc,
r = 0.08;
t = 2;
for n = 1:180,
M(1,n) = r*cos(t); %x length from center
M(2,n) = r*sin(t); %y length from center
t = t+2;
end
It is meant to find the x,y distance from the center of a circle with fixed radius (Basically calculating x,y coordinates of circumference).
However the coordinates are coming wrong and it is because Matlab is performing calculations in radians rather than in degrees. (I cross checked the values with calculator) And I don't know how to convert to radians, and none of the forum results made sense to me.
Thanks, Rohan
Answers (3)
There is a built in function for that:
doc deg2rad
But it is rather trivial to implement it yourself:
myTrans = @(x) x./360.*(2.*pi());
myTrans(180)
ans =
3.1416
6 Comments
James Tursa
on 21 May 2013
To avoid two scalar * vector multiplies, group the constant scalars:
x * (180/pi()); % rad --> deg
x * (pi()/180); % deg --> rad
José-Luis
on 21 May 2013
Thanks. I was just trying to make the formula explicit though.
Rohan Repale
on 21 May 2013
James Tursa
on 21 May 2013
No, you did not have to use sind and cosd. They work, but the many other suggestions on this thread using sin and cos correctly also work.
Rohan Repale
on 21 May 2013
Ivan-V-Timofeev
on 4 Nov 2014
deg2rad
It does not work without toolbox > geo > private > deg2rad.m http://mooring.ucsd.edu/software/matlab/doc/toolbox/geo/private/deg2rad.html
Iain
on 21 May 2013
0 votes
Degrees = 180 * radians / pi.
Rearrange as needed ;)
6 Comments
James Tursa
on 21 May 2013
To avoid two scalar * vector multiplies, group the constant scalars:
Degrees = radians * (180 / pi);
Rohan Repale
on 21 May 2013
Iain
on 21 May 2013
Put the conversion in the right place(s)?
Rohan Repale
on 21 May 2013
Iain
on 21 May 2013
Radians = degrees * (pi/180)
"t" is in degrees, and you want it in radians when put into cos and sin.
cos(t * (pi/180)) and sin(t * (pi/180)) is the conversion rearranged as needed, AND put in the right place...
José-Luis
on 21 May 2013
Doesn't seem to work... How? Please show what you mean.
per isakson
on 21 May 2013
0 votes
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