How would you automate this code?

I have the following situation:
d = [3 39 54 53 6];
n = 103;
What I would like to do is to have a code where: when the sum of the elements in d is bigger than n, then I subtract one from the first column in d that is equal or bigger than n.
In the example above, I would have:
d = [3 39 54 *52* 6];
% since the first column where sum(d) is bigger than n is the fourth column, therefore I subtract 1 from 52
How can I automate this?
Thanks!

 Accepted Answer

Rik
Rik on 9 Feb 2021
Th cumsum and find functions should be useful. Let me know if you have trouble implementing it.

3 Comments

Thanks a lot Rik! I made it, simple and elegant! I don't know why I always get loops first in my head
You're welcome.
Loops are an excellent first step. Matlab is good at optimizing code that is easy to interpret. Loops are the best choice if there isn't a direct function available. Using cellfun (except for the legacy syntax) or arrayfun only hides the loop and tends to have worse performance.
thanks for the tip!

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