# How to solve equation AX=B where A is symmetric like matrix ?

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##### 1 Comment

John D'Errico
on 1 Feb 2021

Think about how you would solve the problem by hand. You would convert it to a problem wehre you mosve the constant (known) terms to the right hand side. Then you would move the unknowns to the left hand side. Now you would create a NEW matrix that would describe that system, and solve it, using backslash.

Or, you could be lazy, just use solve.

### Answers (1)

Shubham Rawat
on 3 Feb 2021

Hi Phanindra,

You may look use this code for your reference:

syms b1 b2 x1 x2

A = magic(4); %random 4*4 matrix

x = [x1;x2;4;5];

b = [6;7;b1;b2];

S = solve(A*x == b); %used solve to solve these equations

% resuls

S.x1

S.x2

S.b1

S.b2

Hope this Helps!

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