Adding a third array for comparison

I have a three main array the consist of sub array themselves and I have managed to combine two of the main array in the loop shown below into a single new array. The issue I am facing is that I am not really certain of how to add the third main array. Here is the issue:

Given: A = {A1 A2 A3} B = {B1 B2 B3} C = {C1 C2 C3}

Desired output: V = {A1+B1+C1 A1+B1+C2 A1+B1+C3 A1+B2+C1 A1+B2+C2 A1+B2+C3 ..... and so on.

Current output: V = {A1+B1 A1+B2 A1+B3 A2+B1 A2+B2 A2+B3 A3+B1 A3+B2 A3+B3}

Code:

b = 1;
i = 1;
v = 1;
if true
    if b <= length(B)
        while b <= length(B)
            V{v} = A{i} + B{b}
            b = b + 1;
            v = v + 1;
        end
    end

    while true
        if b > length(B)
            b = 1;
            i = i + 1;
            if i <= length(A)
                while b <= length(B)
                    V{v} = A{i} + B{b}
                    b = b + 1;
                    v = v + 1;
                end
            else 
                return
            end
        end

    end
end

Answer 1

[Walter Roberson]

V = cellfun(@(m1,m2,m3) m1+m2+m3, A, B, C, 'uniform', 0)

[Andrew Tubbs]

The cellfun command does not work, this outputs an array with three cells, not the 27 cells that the combinations come out to. I am looking for a way to add the third set of array into the current structure of the program.

[Walter Roberson]

[C1, C2, C3] = ndgrid(1:3);
V = arrayfun(@(c1,c2,c3) A{c1}+B{c2}+C{c3}, C1(:), C2(:), C3(:), 'uniform', 0).';

[Andrew Tubbs]

I am not looking for a function, just a litteral addition to the code I have posted in the same format.

[Walter Roberson]

Your code is too complicated

loop over the indices for the elements of A
   loop over the indices for the elements of B
      loop over the indices for the elements of C
         calculate index A plus index B plus index C
         store it to the list of results
      end of loop
   end of loop
end of loop