Index exceeds number of array elements in for loop
Show older comments
I'm trying to replace 0 with NaN if it is present at the 2nd or 6th element of a column vector. I also need to replace with NaN if there are 9 consecutive zeros, or two NaNs if there are 12 consecutive zeros. I then try to remove all the remaining 0s.
RTa = cell2mat(Rxtcell);
if RTa(2) == 0
if RTa(6) == 0
RTa(6) = NaN
end
RTa(2) = NaN;
end
for n = 1:length(RTa)
X = RTa(n:n+8);
X2 = RTa(n:n+12);
Y = [0;0;0;0;0;0;0;0;0];
Y2 = [0;0;0;0;0;0;0;0;0;0;0;0;0];
if X==Y
if X2==Y2
RTa(n+1) = NaN
end
RTa(n) = NaN
end
end
RT1 = RTa(RTa~=0);
Gives the error
Index exceeds the number of array elements (241).
Error in RTscript (line 11)
X2 = RTa(n:n+12);
If I run script or copy-paste and run in workspace respectively.
Accepted Answer
More Answers (0)
Categories
Find more on Image Arithmetic in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!