MATLAB Answers

Reynolds number, FalsePosition getting multiple errors with no output

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Anastasia Zistatsis
Anastasia Zistatsis on 23 Jan 2021
Commented: VBBV on 23 Jan 2021
I am to create a function that uses FalsePosition (function shown below) to solve for f in the given equation. I think I'm missing some connections between my script and the function I'm trying to call.
Here is FalsePosition
This is my code:
function [root, fx, ea, iter] = falsepositionnew(y)
xl = 2500;
xu = 1000000;
es = 0.0000001;
maxit = 200;
Re = 10000:200000;
y = @(f, Re) 1/sqrt(f) - 4*log(Re*sqrt(f))+0.4; %equation given
for = i:numel(Re)
f(i) = falseposition(y,xl,xu,es,maxit);
end

Answers (1)

VBBV
VBBV on 23 Jan 2021
%if true
for i = 1:numel(Re) % change this line
  4 Comments
VBBV
VBBV on 23 Jan 2021
The function also outputs more variables than what its shown in for loop.

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