Row and Cloumn find in cell array
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f={[4,5];[6,8];7; 6;[];9;[8,9];[ ];[ ];[ ]}
ans=find([f{:}] == 6)
% ans= 3 6
I try this;
[row,col]=find([f{:}] == 6)
%row =
1 1
%col =
3 6
but I don't want this, 6 in f cell;
row/col; 2,1 and 4,1
Can u help me for this?
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Answers (2)
Image Analyst
on 1 Jan 2021
Well here's one way.
f={[4,5];
[6,8];
7;
6;
[];
9;
[8,9];
[ ];
[ ];
[ ]}
count = 1;
for k = 1 : length(f)
has6 = find(f{k} == 6);
if ~isempty(has6)
locations{count} = [k, has6];
count = count + 1;
end
end
celldisp(locations)
Not very compact but it is intuitive. Someone will probably give you a one-liner using cellfun().
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Stephen23
on 1 Jan 2021
What you want is actually the cell index and the index of the cell content, not the "row and column" index as you wrote.
f = {[4,5];[6,8];7;6;[];9;[8,9];[];[];[]};
nml = cumsum(cellfun(@numel,f));
idx = find([f{:}]==6);
idr = 1+sum(nml<idx,1)
idc = idx(:)-nml(idr-1)
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