I'm getting the error "Array indices must be positive integers or logical values." and it seems like I structures the for loop to handle the equations. Can anyone help me with this?
2 views (last 30 days)
Show older comments
Matthew Williams
on 13 Dec 2020
Answered: Gouri Chennuru
on 16 Dec 2020
ds=zeros(length(y),1);
dAs=zeros(length(y),1);
Ac=zeros(length(y),1);
for j=1:N
t1=(t(y(j))+t(y(j+1/2)))/2; %average thickness of CV on side closer to y=0
t2=(t(y(j-1/2))+t(y(j)))/2; %avgerage thickness of CV on side closer to y=L
ds(j)=sqrt((t(y(j+1))-t(t(j-1))).^2+(2*dy).^2)/2; %using central difference
dAs(j)= (w+((t1+t2)/L))*ds(j)*dx; %surface area
Ac(j)=(t(y(j)))*dx; %Cross sectional area
end
3 Comments
Walter Roberson
on 13 Dec 2020
You cannot index at half-integers . You can index a value and divide the result by 2, though.
Accepted Answer
Gouri Chennuru
on 16 Dec 2020
Hi Matthew,
As per my understanding, you are trying to extract the variable "y" with indices (j+1/2) and (j-1/2), from the following lines.
t1=(t(y(j))+t(y(j+1/2)))/2;
t2=(t(y(j-1/2))+t(y(j)))/2;
You cannot point arrays to a particular decimal index.As a workaround make sure that array Index is always a positive integer or a logical value.
Regards,
Gouri Chennuru
0 Comments
More Answers (0)
See Also
Categories
Find more on Matrices and Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!