Elegant / Vectorized way of getting array from start_index vector and end_index vector?

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Hello
Suppose start_index = [1 5 10]; and end_index = [3 8 12];
Is there an elegant solution to get an output of [1 2 3 5 6 7 8 10 11 12], that is the function takes each start value and gives all inclusive values between the start and end value, repeats with the next index, until all inclusive values are included in a single output vector?
Thank you

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 16 Mar 2013
Edited: Azzi Abdelmalek on 16 Mar 2013
EDIT
v=[1 2 3 5 6 7 8 10 11 12]
start_index = [1 5 10];
end_index = [3 8 12];
out=cell2mat(arrayfun(@(x,y) x:y,start_index, end_index,'un',0))
out=intersect(out,v)

More Answers (1)

Jan
Jan on 16 Mar 2013
Edited: Jan on 16 Mar 2013
start_index = [1 5 10];
end_index = [3 8 12];
index(end_index + 1) = -1; % Implicit pre-allocation
index(start_index) = 1;
result = find(cumsum(index));
In many cases logical indexing is more efficient:
result = (cumsum(index(1:end-1)) == 1);
An even more efficient method is FEX: mcolon.

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