Logical comparison (>= to be specific) between each element (row) of a column vector, and all elements inside each row of a matrix having same number or rows, respectively

I am wondering if there is a better/faster way to do this, perhaps without a for loop?

Say, I have a 30x50 matrix A, and a 30x1 column vector B. I want to procuce a 30x50 logical matrix C, where each element of C is 1 if the corresponding element of A is greater than or equal to the element of B located on the same row as that element.

For a small example:

>> A = [1 2 3 4 5 6; 7 8 9 10 11 12; 13 14 15 16 17 18];
B = [4 10 16]';
%numbers are in ascending order to simplify example
C = false(3,6);
c = 1;
for k = B'
   C(c,:) = (A(c,:) >= k);
   c = c + 1;
end

The output:

C

C =

  3×6 logical array

   0   0   0   1   1   1
   0   0   0   1   1   1
   0   0   0   1   1   1

Answer 1

[Stephen Cobeldick]

A = [1,2,3,4,5,6;7,8,9,10,11,12;13,14,15,16,17,18]

A = 3×6

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

B = [4;10;16]

B = 3×1

4 10 16

C = A>=B % requires >=R2016b

C = 3x6 logical array
   0   0   0   1   1   1
   0   0   0   1   1   1
   0   0   0   1   1   1

C = bsxfun(@ge,A,B) % for earlier versions

C = 3x6 logical array
   0   0   0   1   1   1
   0   0   0   1   1   1
   0   0   0   1   1   1

[Jonathan Morcos]

Wow, I feel quite silly. I don't know why I didn't think that would work. Thank You!