# How to create a periodic function?

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### Accepted Answer

James Tursa
on 25 Nov 2020

Not sure what you mean by "repeated at [2,10]". Maybe this:

y = mod(x,2);

ix = y > 1;

y(ix) = 2 - y(ix);

##### 9 Comments

James Tursa
on 25 Nov 2020

Generic code could be:

% Periodic triangle wave

amplitude = whatever;

period = whatever;

y = mod(x,period);

ix = y > period/2;

y(ix) = period - y(ix);

y = (amplitude * 2 / period) * y;

### More Answers (2)

David Hill
on 25 Nov 2020

y=zeros(size(x));

for k=1:5

y(x>=(k-1)*2&x<(k-1)*2+1)=x(x>=(k-1)*2&x<(k-1)*2+1);

y(x>=2*(k-1)+1&x<2*k)=2-x(x>=2*(k-1)+1&x<2*k);

end

##### 4 Comments

Image Analyst
on 25 Nov 2020

Then just use the code that you used to create the figure. It's what you want isn't it?

Setsuna Yuuki.
on 25 Nov 2020

You can use this function: https://es.mathworks.com/matlabcentral/fileexchange/83058-continuous-piecewise-function-linear-funcion-por-partes

x = [0:3:36];

y = [0 1 0 1 0 1 0 1 0 1 0 1 0];

sig = pwfun(x,y);

and create the waveform only with the intersection points.

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