For loop help!

I need helpt with a for loop to pick numbers from a vector and put them in an existing non square in the order shown in the figure below (hop it makes sense). It starts at the dot and then follow the arrow. the resulting matrix should be as the one in the blackbackgrownd figure.

Sorry if this has been asked before <3 .

Thank you.

[James Tursa]

Is this just for the specific problem you show (in which case you can simply use explicit indexing since the problem is small enough)? Or is there really a bigger problem you are trying to solve?

[BiaoZhun]

Hello James, thanks for replying.

The actual problem is a vector of size118668x1 to be put in a matrix of size 9889x12 so becase of the amount of data i need a for loop :S

[James Tursa]

Well, you don't necessarily need a for-loop. We just need to know the explicit indexing rule for your large vector.

[BiaoZhun]

The indexing patter should be as the same way as in the figure with the arrows, for which I hope the figure makes sense.

[James Tursa]

Start with 3 and increment by 3's, then start with 2 and increment by 3's, then start with 1 and increment by 3's?

[BiaoZhun]

yes, but it has to start one after the other, starts with 3(lets say n) and increments by 3's and then goes through the whole vector and then starts 2(n-1) an incremebts by 3's then goes through the whole vector agian, and then starts at 1(n-2) and increments by 3's. Hope this makes a better idea of the problem.

Answer 1

[Stephen Cobeldick]

"... so becase of the amount of data i need a for loop"

I doubt that using a loop would be a good approach.

V = 1:12;
R = 3;
M = flipud(reshape(V,R,[]))

M = 3×4

3 6 9 12 2 5 8 11 1 4 7 10

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Your larger vector:

V = rand(118668,1);
R = 9889;
M = flipud(reshape(V,R,[]));
size(M)

ans = 1×2

9889 12

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