Code Block of Operates in Image Processing

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I tried this:
%Take negative
%positiveImage = imread('cameraman.tif');
%negativeImage = 255 - positiveImage;
%imshow(negativeImage)
%or
1) a=imread('cameraman.tif');
d(:, :, 3) =255 - a(: ,:, 3);
d(: ,:, 2) = 255 - a(:, :, 2);
d(:, :, 1) =255 -a(:, :, 1);
imshow([a,d])
%log transformation with c=10
clc; clear all; close all;
f=imread('cameraman.tif')
g=rgb2gray(f);
c=input('Enter the constant value, c= 10');
[M,N]= size(g);
for x=1:M
for y=1:N
m= double(g(x,y));
z(x,y)= c. *log10(1+m);
end
end
imshow(f), figure, imshow(z);
%power-law with c=10, gamma=0.5
clc; clear all; close all;
RGB=imread(' cameraman.tif');
I=rgb2gray(RGB);
I=im2double(I);
[m,n]= size(I);
c=10;
g=[0.5];
for r= 1:length(g)
for p=1:m
for q=1:n
I3=(p,q) =c *I(p,q). ^ g(r);
end
end
figure, imshow(I3); title('Power law transformation'); xlabel('Gamma='), ylabel(g(r));
end
%contrast stretching
I=imread('cameraman.tif');
[m,n]=size(I);
figure, imshow(I);
minp=min(min(I));
maxp=max(max(I));
maxp=double(maxp);
minp=double(minp);
c=10;
d=255;
for i=1:m
for j=1:n
sonuc=(((d-c)/(maxp-minp))*(double(I(i,j))-minp))+c;
B(i,j)=round(sonuc);
end
end
B=uint8(B);
figure, imshow(B);

Accepted Answer

Image Analyst
Image Analyst on 17 Nov 2020
In the middle of the loop, call a function that processes one image only and returns an output image. Then call sprintf() to create an output name, then call imwrite() to save the output image to that output file name.
  9 Comments
Rooter Boy
Rooter Boy on 18 Nov 2020
Edited: Rooter Boy on 19 Nov 2020
Sir, could you help me when you are available? you are professional at matrix operates in matlab.
Image Analyst
Image Analyst on 19 Nov 2020
Sorry, I don't know much about that topic and don't understand what or why you think something's wrong with the code.

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