How to apply spatially-varying blur to an image?

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Hi
I have an image of size 128x128, and an associated a blur map, where each element defines the size of the blur kernel. How can I apply this blur map to the image so that each pixel is blurred differently?
Thank you very much.
  2 Comments
Matt J
Matt J on 18 Oct 2020
How is it enough to know the size of the local blur kernel? What about its shape?
xiaojuezi
xiaojuezi on 18 Oct 2020
I think any smoothing filter can be applied, for example a standard Gaussian filter.

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Answers (1)

Image Analyst
Image Analyst on 18 Oct 2020
See my manual convolution demo. You'll need to change it to make the inner loops change their starting and ending values depending on the size of the blur window you read from your blur map (which hopefully is composed of only odd numbers). Should be really, really easy with only about 2 lines needing to be added
  1. call blurmap = imread(filename) to read in your blur image.
  2. get the blur window width between the second and third for loop by reading the blurmap at that row and column:windowWidth = blurmap(row, column)
and two to be modified -- the limits on the inner two for loops.
But let me know if you can't figure it out and attach your blur image.
  2 Comments
xiaojuezi
xiaojuezi on 18 Oct 2020
Thank you very much for your answer and your script! I have one question, I think the limits of the two outer for loop also need to be changed. How do you decide these limits since each pixel now has a different windowSize?
Image Analyst
Image Analyst on 19 Oct 2020
Yes, good point. Depends on how much work you want to go into to handle the edge effects. One way is to just determine the starting and ending rows and columns by getting the max of the whole blur map and use that. What's wrong with that? I mean how much difference does it make REALLY to be more accurate near the edges? Probably won't make a noticeable difference so just go with the easiest route, which is to use the largest window.
What's the use case? Why do you want the blur to vary by location anyway?

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