I tried to solve problem but I couldn'!

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Write a function called between that takes one scalar and two vectors of the same length as input arguments (the function does not have to check the format of the input) and returns one scalar output argument. If it is called like this, n = between(a,u,v), then n is equal to the number of indices ii for which the scalar a is between u(ii) and v(ii) or a is equal to u(ii) or v(ii). Here are some examples for the case in which the length of the vectors is 4:
  1 Comment
zehra ülgen
zehra ülgen on 18 Oct 2020
>> n = between(4,[5,0 -7 6], [3, 9, 4, 4])
n =
4
>> n = between(5,[5,0 -7 6], [3, 9, 4, 4])
n =
3
>> n = between(6,[5,0 -7 6], [3, 9, 4, 4])
n =
2
>> n = between(9,[5,0 -7 6], [3, 9, 4, 4])
n =
1
>> n = between(10,[5,0 -7 6], [3, 9, 4, 4])
n =
0

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Accepted Answer

Payam Morsali
Payam Morsali on 18 Oct 2020
function y=compare(n,A,B)
y=0;
for i=1:length(A)
if n>=A(i) && n<=B(i)
y=y+1;
elseif n>=B(i) && n<=A(i)
y=y+1;
end
end
end
  3 Comments
John D'Errico
John D'Errico on 19 Oct 2020
Please don't do assignments for people when they show no effort to do it themselves. This teaches them nothing, except how to get someone else to do their work for them.
zehra ülgen
zehra ülgen on 19 Oct 2020
I tried to solve problem.. That's my answer in a different way..
function n = betweenn(a, u, v)
n = sum((u <= a & a <= v) | (v <= a & a <= u));
end

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