str in a IF statement, PLEASE HELP
Show older comments
Thats what I asked to do.

This is my code so far. But its not working for the str and complex part. Can anyone kindly help me?
p = input('To play the game, enter a shooting angle between -90 and 90 degree: ');
for i = 1 : p
if p(i) <= -90 || p(i) >= 90
disp('Enter a real number between -90 and 90 degree!!!');
break
elseif p(i) == 'str'
disp('Enter a real number between (-90~90) rather than string');
break
elseif p(i) == 'complex'
disp('Enter a real number between (-90~90) rather than any complex number')
break
end
end
Accepted Answer
More Answers (1)
- Why do you have a loop when the instructions ask for a single value?
- The use of break usually indicates inefficient coding. Again, I don't see a reason to have a for-loop to begin with. Even with the loop. I don't understand why you would break after the first iteration.
- Instead of using conditional statements to confirm that the user entered a valid response, use input validation such as validateattributes (doc).
validateattributes(p,{'numeric'},{'scalar','>=',-90,'<=',90},mfilename,'input')
Test some results
% When p is a string
p = '5';
ERROR:
Expected input to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64
% When p contains more than 1 value
p = [1 2];
ERROR:
Expected input to be a scalar.
% When p is a value out of range
p = -180;
ERROR:
Expected input to be a scalar with value >= -90.
p = 100;
ERROR
Expected input to be a scalar with value <= 90.
Categories
Find more on Characters and Strings in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!