Plot contour lines on top of imagesc?

23 views (last 30 days)
Hi,
I'm trying to make a contour plot with one of the variables being discrete (integer). I try to combine somehow the 2 following plots:
y = [1:10]';
x = 1:0.01:10;
z = repmat(y, [1,901]) - repmat(x, [10,1]);
figure
subplot(2,1,1)
contourf(x,y,z)
xlabel('x (continuous)');
ylabel('y (discrete)')
subplot(2,1,2)
imagesc(flipud(z))
xlabel('x (continuous)');
ylabel('y (discrete)')
colormap(jet(256))
In the top panel I have a (filled) contour plot but the lines are diagonal (not step-like) so this is not good for integer y values. The bottom plot shows the discrete y values and (almost) continuous x values but I don't know how to draw the contour lines on top of this? Is there a quick way of doing this?
Thanks!

Accepted Answer

Sean de Wolski
Sean de Wolski on 12 Dec 2012
Edited: Sean de Wolski on 12 Dec 2012
You can specify x/y for imagesc so that the image is not shown against its index. From there you can simply use hold on and contour:
y = [1:10]';
x = 1:0.01:10;
z = repmat(y, [1,901]) - repmat(x, [10,1]);
figure
subplot(2,1,1)
contourf(x,y,z)
xlabel('x (continuous)');
ylabel('y (discrete)')
subplot(2,1,2)
imagesc(x,y,flipud(z)) %specify x/y
xlabel('x (continuous)');
ylabel('y (discrete)')
colormap(jet(256))
hold on %hold it on
contour(x,y,flipud(z),'color','k') %contour over it
More per Comments
In that case I would grab the 'CData' from the image and bin it using histc (essentially replacing image values with indexes into contour levels). Then draw a contour plot of this.
y = [1:10]';
x = 1:0.01:10;
z = repmat(y, [1,901]) - repmat(x, [10,1]);
figure
subplot(2,1,1)
contourf(x,y,z)
xlabel('x (continuous)');
ylabel('y (discrete)')
subplot(2,1,2)
h = imagesc(x,y,flipud(z));
xlabel('x (continuous)');
ylabel('y (discrete)')
colormap(jet(256))
hold on
D = get(h,'CData'); %image data
[~,idx] = histc(D,linspace(m(min(D)),max(max(D)),10)); %bin it
contour(x,y,idx,'color','k') %contour of the bins
  5 Comments
Razvan
Razvan on 13 Dec 2012
Nevermind... I figured it out now... Thanks for your answer. That helped me.
Sean de Wolski
Sean de Wolski on 13 Dec 2012
You're welcome!
I would image it just came down to changing the edges in the call to histc()?

Sign in to comment.

More Answers (0)

Categories

Find more on Contour Plots in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!