Month as a two digit number

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alpedhuez
alpedhuez on 2 Jul 2020
Commented: alpedhuez on 3 Jul 2020
I have
month(Date);
this will give me the number 1,2,3,...
But I want to have 01,02,03,.. as months. Please advise.
  3 Comments
alpedhuez
alpedhuez on 3 Jul 2020
Eventually want to create yyyy-mm variable
yyyy_mm=strcat(num2str(year),'-',num2str(month));
and I want to have "month' as a two digit number so that output is like '2020-01'.
dpb
dpb on 3 Jul 2020
Edited: dpb on 3 Jul 2020
Hadn't seen this comment ere now--
Again, use the proper variable class for the purpose --
>> Date = datetime('now') % build the date variable -- how is up to your application
Date =
datetime
03-Jul-2020 12:39:53
>> Date.Format='yyyy-MM' % set the desired display format--anything that uses will be as shown on output
Date =
datetime
2020-07
>> string(Date) % if you really must have a string or cellstr(), it's what you get automagically
ans =
"2020-07"
>> disp(Date) % or just use the variable; its output format is as requested
2020-07
>>
As another poster noted, do NOT use month as a variable; that aliases the builtin month() function.

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Answers (2)

Star Strider
Star Strider on 2 Jul 2020
To have leading zeros, it has to be a character array or string variable.
Try this:
Date = datetime('now');
mth = sprintf('%02d',month(Date));
producing:
mth =
'07'
.
  3 Comments
madhan ravi
madhan ravi on 2 Jul 2020
Edited: madhan ravi on 2 Jul 2020
Date = datetime('now',"Format",'MM') % which is what i mean't in my comment ;)
Star Strider
Star Strider on 3 Jul 2020
I also didn’t see this Comment until now.
Expanding on my initial Answer:
Date = datetime('now')+calmonths(0:3).';
Date.Format = 'yyyy-MM';
Out = Date
produces:
Out =
4×1 datetime array
2020-07
2020-08
2020-09
2020-10
.

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madhan ravi
madhan ravi on 2 Jul 2020
Edited: madhan ravi on 3 Jul 2020
ix = m < 10 % m is the output of the month(...) , by the way it can be set by Format in datetime(...)
M = "" + m
M(ix) = 0 + "" + m(ix)
  4 Comments
madhan ravi
madhan ravi on 3 Jul 2020
Edited: madhan ravi on 3 Jul 2020
yyyy_mm = datetime("now","Format","uuuu-MM")
m = randi([1, 12], 10, 1); % months example
ix = m < 10 ;
M = "" + m;
M(ix) = 0 + "" + m(ix)
Note: Naming a variable month is a terrible idea!!!
alpedhuez
alpedhuez on 3 Jul 2020
Let me work on it.

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