Adding a global legend to a tiledlayout
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Christian Schröder
on 4 Jun 2020
Commented: Carl Oscar
on 13 Feb 2025 at 14:21
Good morning,
I'm using MATLAB R2020a Update 2. I have a tiledlayout of five (three by two) area plots and would like to use the sixth, currently empty, tile to add a global legend. I've already found this question, and understand that there's no official, built-in way of doing this, but perhaps it's possible to get creative.
What I've tried is adding a new, empty area plot to the sixth tile, using NaNs as the shares, then adding a legend to that and setting the axis object for that tile to invisible, as follows:
% ...
ax = nexttile;
area([NaN NaN], NaN(2, 4));
leg = legend({'tar', 'sta', 'ext', 'dmp');
leg.Location = 'none';
leg.Interpreter = 'latex';
leg.FontSize = 16;
ax.Visible = false;
This works in principle, but leaves a horizontal line where the X axis would be:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/309950/image.png)
This only happens when I use area(), not e.g. plot(). Perhaps it's a bug, perhaps it's intentional and due to the way area() works. In any case it's not what I want, but I can't get rid of it (without breaking other things in the process).
I had the idea of making the children of this axis, i.e. the areas of the area plot, invisible as well, like so:
for i = 1:length(ax.Children)
ax.Children(i).Visible = false;
end
But while this gets rid of the horizontal line it also grays out the legend entries:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/309953/image.png)
This behavior in turn is known and expected and apparently cannot be changed. The workaround suggested by a Mathworks staffer in the linked question is to plot NaNs; but that's what I'm already doing and what's leaving the horizontal line, due to area()'s quirks.
Can anyone help?
I'm not hung up on specifically creating an invisible area(), this is merely the best (first, only) idea I had for fudging a global legend. If anyone can make this approach work, that'd be wonderful. If anyone has another idea of how to achieve a similar effect, that'd be wonderful as well.
Thank you very much!
0 Comments
Accepted Answer
Rik
on 4 Jun 2020
I can't get the position quite right, maybe you have more luck with your tinkering. This at least gets rid of the line. (I guess this is what you meant with boiler plate code in your answer here)
The new tools (like tiledlayout) have some advantages over using subplot, but this hasn't convinced me so far.
rng(4);
figure(1),clf(1)
tiledlayout(3,2);
for n=1:5
nexttile
Y=rand(30,4);Y=Y./sum(Y,2);
area(Y)
end
ax = nexttile;
p_ax=ax.Position;
area([NaN NaN], NaN(2, 4));
leg = legend({'tar', 'sta', 'ext', 'dmp'});
p_leg=leg.Position;
delete(ax)
ax=axes('Position',[p_ax(1:2) 0 0]);
area([NaN NaN], NaN(2, 4));
leg = legend({'tar', 'sta', 'ext', 'dmp'});
leg.Location = 'none';
leg.Interpreter = 'latex';
leg.FontSize = 16;
ax.Visible = false;
leg.Position=p_leg;
More Answers (3)
Adam Danz
on 29 Sep 2020
Edited: Adam Danz
on 30 Jan 2023
Update
As of Matlab r2020b, legend location can be specified relative to axes created within an TiledLayout. This demo below produces 1x4 tiles of axes and the adds a legend to the East of the layout.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/368638/image.png)
% DEMO
fig = figure();
fig.Position(4) = 225;
colors = [winter(3);summer(3);autumn(3);copper(3)];
subPlotNames = 'ABCD';
h = gobjects(3,4);
tiledlayout(1,5)
for i = 1:4
ax = nexttile;
h(:,i) = plot([0,1],[.66;.5;.33].*[1,1],'LineWidth',4);
text([.1,.1,.1],[.66;.5;.33],{'1' '2' '3'},'VerticalAlignment', 'Bottom')
set(h(:,i), {'DisplayName'}, compose('%s %d',subPlotNames(i),1:3)')
title(subPlotNames(i))
end
set(h(:), {'Color'}, mat2cell(colors,ones(12,1),3))
lg = legend(h(:));
lg.Layout.Tile = 'East'; % <-- place legend east of tiles
Rubens R. Fernandes
on 15 Jun 2022
Edited: Rubens R. Fernandes
on 15 Jun 2022
I think I got a solution for this!
In my case, I am using a tiled layout of (2x2), and the legend is defined on the data plotted for the first layout.
What I got is:
figure
%Defines the variables
x=linspace(1,10,10);
y1=x;
y2 = 2.*x;
y3 = 3.* x;
%Initiates the figure
tiledlayout(2,2)
%Plots the data in tile 1
nexttile(1)
plot(x, y1, 'DisplayName', 'y1');
hold on
plot(x, y2, 'DisplayName', 'y2');
hold on
plot(x, y3, 'DisplayName', 'y3');
%Plots the data in tile 2
nexttile(2)
plot(x, y1.^2, 'HandleVisibility', 'Off');
hold on
plot(x, y2.^2, 'HandleVisibility', 'Off');
hold on
plot(x, y3.^2, 'HandleVisibility', 'Off');
%Plots the data in tile 3
nexttile(3)
plot(x, y1.^3, 'HandleVisibility', 'Off');
hold on
plot(x, y2.^3, 'HandleVisibility', 'Off');
hold on
plot(x, y3.^3, 'HandleVisibility', 'Off');
%Plots the legend in tile 4
ax = nexttile(1);
lg = legend('Orientation','Vertical','NumColumns',2, 'Interpreter', 'Latex');
lg.Layout.Tile = 4; % THIS IS THE COMMAND THAT WILL SET THE TILE WHERE YOU WANT TO PLOT YOUR LEGEND
Hope it helps!
2 Comments
Alexander
on 10 Jul 2024
When a tiledlayout is created, it automatically creates 4 extra tiles ('north','east','south','west') around the layout you initially declare. You can create one legend after you are finished plotting, and place it in one of these locations like this.
data1 = randn(100,4);
data2 = randn(100,4);
tiledlayout(2,2);
for tile = 1:4
nexttile()
plot(data1(:,tile),'DisplayName','Data1')
hold on
plot(data2(:,tile),'DisplayName','Data2')
end
lgd = legend;
lgd.Layout.Tile = 'east';
This code will plot 4 graphs in a 2x2 layout. In my loop I increment by one tile and plot Data1 in blue and Data2 in red. After finishing the loop, I create the legend and put the legend in the eastern tile.
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