# Simple Iterative expression needed solved

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James Paltani on 30 Apr 2020
Commented: Walter Roberson on 30 Apr 2020
Assuming w is an integer (w = 1, 2, 3, …), write an iterative calculation to determine the minimum w value that will bring the result of the following expression to greater than 10,000. Display this minimum w value and the corresponding result of the expression.

Walter Roberson on 30 Apr 2020
initialize. while the condition is not met, increment.
James Paltani on 30 Apr 2020
Edited: James Paltani on 30 Apr 2020
This is what i have so far.. it says illegal "greater than" operator. What should i differently
clc,clear
syms w
e = sqrt((10*w^2)-4*w+2);
for e > 10000,
solve(w)
Walter Roberson on 30 Apr 2020
syms w
e = sqrt((10*w^2)-4*w+2);
w = ceil(max(double(solve(e==10000))));
But this does not use a loop like you are required to do. You should not be using symbolic toolbox for this problem.
You should be initializing w to the lowest value of the range. Then you calculate e based on that w. Test whether it has reached the necessary value yet. If it has not, increment w and recalculate e and loop back.

Mrutyunjaya Hiremath on 30 Apr 2020
w = 1; y = 0;
while(y < 10000)
y = sqrt(10*w*w - 4*w + 2);
w = w + 1;
end
disp(w)
disp(y)
Walter Roberson on 30 Apr 2020
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