How do I draw barh using both axes values?

Hi All

How do I draw barh ( horizontal bars) taking into consideration both axes values : saying when 0<x<100 , draw a bar between 10<y<12

[Ameer Hamza]

Can you show an image of your expected output?

Answer 1

[Walter Roberson]

x_to_draw_at = x(0 < x & x < 100);
bar(x_to_draw_at, 12*ones(1,length(x_to_draw_at)), 'basevalue', 10)

[farzad]

Thank you Walter, I get error : cause the x limits in first paranthesis are not known

>> x_to_draw_at = x(0 < x & x < 100);
bar(x_to_draw_at, 12*ones(1,length(x_to_draw_at)), 'basevalue', 10)
Unrecognized function or variable 'x'.

by the way , the bars should be horizontal. does the code do this ?

[farzad]

ok I got it and made it run. does it work the same as figure ? how to save it from app designer ?

[farzad]

dear Wiliam

there is a problem , I did the following :

ranged = ranges(0 < ranges & ranges < max(ranges)*1.1)

for the vertical axis of barh , but then the minimum limit on the axis goes to under zero, but I want the minimum level be always zero. how do I do that ?

[Walter Roberson]

For values of ranges, by definition ranges <= max(ranges). When ranges is entirely positive, then max(ranges) is positive and max(ranges)*1.1 is even larger than max(ranges) so you can be sure that ranges < max(ranges)*1.1 .

So when could ranges < max(ranges)*1.1 be false?

1. max(ranges) is 0, in which case 0*1.1 is 0, and 0 < 0 is false. On the other hand, the case of 0 is already eliminated by 0 < ranges
2. max(ranges) is negative, in which case max(ranges)*1.1 is more negative, and it could be the case that there are some values that are more negative than max(ranges) but not as negative as max(ranges)*1.1. For example, -10.5 and -10, max() is -10, max()*1.1 is -11, and -10.5 < -11 is false. However, this can only happen for negative values, never for positive values, and you already eliminate negative values with 0 < ranges .

You should reconsider your test. Perhaps you want something like max(ranges)*0.9

by the way , the bars should be horizontal. does the code do this ?

You are going to need to describe what the output should look like: we as outsiders need to assume that the x values are not sorted and not continuous.