How to search for different values in a 2-D Array using a for loop
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I have been given this question:
I have written this code below but it doesn't seem to work it skips all the iff statments and im not sure why. The array in which i am inputing does have values which should create results. Anyone know what i am doing wrong??
function [wh_1, wh_3, wh_5, wh_7, wh_9, wh_11, wh_13] = count_table(table, col, row)
for m = 1:col
for n = 1:row
if isequal(table(n,m), 0)
wh_1 = wh_1 + 1;
elseif isequal(table(n,m), 1)
wh_1 = wh_1 + 1;
elseif isequal(table(n,m), 2)
wh_3 = wh_3 + 1;
elseif isequal(table(n,m), 3)
wh_3 = wh_3 + 1;
elseif isequal(table(n,m), 4)
wh_5 = wh_5 + 1;
elseif isequal(table(n,m), 5)
wh_5 = wh_5 + 1;
elseif isequal(table(n,m), 6)
wh_7 = wh_7 + 1;
elseif isequal(table(n,m), 7)
wh_7 = wh_7 + 1;
elseif isequal(table(n,m), 8)
wh_9 = wh_9 + 1;
elseif isequal(table(n,m), 9)
wh_9 = wh_9 + 1;
elseif isequal(table(n,m), 10)
wh_11 = wh_11 + 1;
elseif isequal(table(n,m), 11)
wh_11 = wh_11 + 1;
elseif isequal(table(n,m), 12)
wh_13 = wh_13 + 1;
elseif isequal(table(n,m), 13)
wh_13 = wh_13 + 1;
end
end
end
end
Here is the error in which is produced:
Output argument "wh_1" (and maybe others) not assigned during call to "count_table".
Error in (line 44)
[z_1, z_3, z_5, z_7, z_9, z_11, z_13] = count_table(wave_data, 60, 498);
1 Comment
Stephen23
on 30 Mar 2020
The cause of the error is that none of the variables wh_1, etc. exist before you try to reference them:
wh_1 = wh_1 + 1;
% ^^^^ is not defined.
However the entire code is far too complex for this task.
Numbered variables are usually a sign that something is wrong: most likely they should be replaced with one variable.
Accepted Answer
Shishir Singhal
on 9 Apr 2020
Edited: darova
on 9 Apr 2020
Please declare all variables like wh_1, wh_3 and set them to 0 at the beginning of your code. It should work fine.
And for specifiying conditions, you can also try like
if(table(n,m) >=0 && table(n, m)<=1)
wh_1 = wh_1+1;
elseif(table(n, m)<=2 && table(n, m)<=3)
wh_3=wh_3+1;
and so on.
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