# access the respective values of matrix using the cell array cell position value

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Elysi Cochin on 17 Mar 2020
Commented: Elysi Cochin on 17 Mar 2020
i have a matrix as shown in figure, with positions marked
I have a cell array with values
{ [ 1 4 ] ; [ 2 3] };
Now i want to take the values from position
{ [0-1 1-4] ; [0-2 2-3] } of the matrix
i.e. { [ 33 45]; [34 30] }
and get the sum of
33 + 45 +34 +30 = 142
how can i access the respective values of matrix using the cell array cell position values?

Sriram Tadavarty on 17 Mar 2020
Edited: Sriram Tadavarty on 17 Mar 2020
Hi Elysi,
Here is what you have asked for
% Given matrix
a = [0 33 34 16 25;...
22 0 20 12 45;...
20 40 0 30 12;...
16 12 30 0 44;...
34 56 26 15 0];
% Cell positions
cellValue = {[1, 4], [2 3]};
% To make it generic, for any number of cell elements with varying size, you can use a for loop
s=0;
for i = 1:numel(cellValue)
cellInd = cellValue{i};
tmp = [];
tmp(1) = a(0+1,cellInd(1)+1);
for j = 2:length(cellInd)
tmp = [tmp a(cellInd(j-1)+1,cellInd(j)+1)];
end
s = sum(tmp) + s;
end
Hope this helps.
Regards,
Sriram
Elysi Cochin on 17 Mar 2020
Thank you sir, got it