Code To Extract Data From .txt File to Excel
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Hi,
I have several text files with two columns and usually 2000+ rows (picture below). I would like to have some code to extract the value from the bottom row of the second column and put it into an Excel file in a certain place. Each of the text files has a different heading/name (same format as picture below though) and I would like to put the value from the text file into Excel under these headings. If necessary, I can create the headings myself and would be happy to just have code which outputs the same heading's value in the same column each time.
Currently I am doing this manually which takes a long time and will need doing lots more in the future.
Does anyone know how to do this and could help me? Happy to answer more questions or give more details.
Many thanks

4 Comments
Jack Morgan
on 17 Mar 2020
Jack Morgan
on 17 Mar 2020
Edited: Jack Morgan
on 17 Mar 2020
Guillaume
on 17 Mar 2020
Firstly, if you end up copy/pasting the same code and doing slight tweaks to each copy, there's always a better of doing that. Computers are very good at doing repetitive tasks, so why are you doing the repetition yourself.
Now, with regards to your question, can you attach two different example of the files your dealing with. We don't need the full files, the first 10 rows would suffice. Screenshots are not very useful, we can't import them in matlab. Actual files are much better.
Note that for a number of years now, matlab has functions that make importing text files very easy, see readmatrix or readtable. They're usually much easier to use than textscan, they open and close the file for you, usually figure out the header, delimiter and format themselves, and output directly a matrix or table.
"A lot of the files have unique names so I will have to copy the code and change the names for the text file referenced". Again, copy-pasting and modifying code is the wrong approach. Let the computer do the repetition. The basics would be:
- write a generic function that takes the full filename as an input and does whatever processing that needs to be done.
- Obtain the list of file some way, possibly just a dir call with the appropriate filter. At worse, input the list of file as a cell array
- Loop over the list of file, calling the function for each file.
"This creates the array of the results below but each number has brackets [...] Does anyone know how to get rid of these brackets? I tried using erasePunctuation and isstrprop but could not get them to work"
I'm afraid you're lacking some basic understanding of matlab here. I'm not the free course matlab onramp covers cell arrays, but if you haven't done that course, I'd recommend you go through it anyway. What you show is a cell array containing matrices. The brackets are the way matlab shows to you that the cell array contains matrices. The brackets are not part of the data. They're only for display. Trying to use erasePunctuation on something that is not text at all is meaningless.
In any case, if you use readmatrix you'd be dealing with matrices directly. Please attach examples so I can show you better code.
Jack Morgan
on 17 Mar 2020
Edited: Jack Morgan
on 17 Mar 2020
Accepted Answer
More Answers (2)
Kevin Chng
on 17 Mar 2020
Accept my answer if it is working for you. Thanks
fid = fopen('12.txt','rt');
indata = textscan(fid, '%f %f', 'HeaderLines',3);
fclose(fid);
%your data is in indata
Image Analyst
on 17 Mar 2020
0 votes
To process a sequence of files, place your code in the middle of a for loop over files.
For code samples, see the FAQ: FAQ#How_can_I_process_a_sequence_of_files?
2 Comments
Jack Morgan
on 17 Mar 2020
Walter Roberson
on 17 Mar 2020
Is there any pattern that can be used to distinguish the files you want to process from the other ones you do not want to process in the same directory? For example do you want to process all of the *moment-z-rfile.txt files? If so then you can use
dinfo = dir('*moment-z-rfile.txt');
filenames = {dinfo.name};
numfiles = length(filenames);
for K = 1 : numfiles
thisfile = filenames{K};
[folder, basename, ext] = fileparts(thisfile);
outfile = fileparts(folder, [basename '.out']);
....
end
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