How to construct an array from two arrays of different sizes using conditional replacement of elements?
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Hi, I have two arrays A and B as below
A=load('A.txt');
B=load('B.txt');
where
A=
1
2
3
4
5
6
7
8
9
10
and
B=
1 4
3 10
6 15
8 17
9 59
Goal: I want to construct an array C with the same length as A. The elements of C equals the elements of the second column of B if the elements of the first column of A and the elements of the first column of B are equal. Otherwise, the elements of C is not available (NaN)
Thus, C should look like below:
C=
1 4
2 NaN
3 10
4 NaN
5 NaN
6 15
7 NaN
8 17
9 59
10 NaN
I tried the following command lines:
C=zeros(size(A));
for i=1:numel(A);
for j=1:numel(B);
if A(i)=B(j);
C(i)=B(j,2);
else
C(i) = NaN;
end;end;
but had no success yet. I wonder if someone could help me to correct the mistakes I have done or suggest something else that works.
I thank you in advance for you help
Emerson
2 Comments
Andrei Bobrov
on 25 Oct 2012
A=[
1
2
3
4
5
6
7
8
9
10],
B=[
1 4
3 10
6.5 15
8 17
7.4 47
9 59]
out = [A, nan(numel(A),1)]
[a,b] = ismember(A,B(:,1))
out(a,2) = B(b(a),2)
Accepted Answer
Azzi Abdelmalek
on 15 Oct 2012
Edited: Azzi Abdelmalek
on 15 Oct 2012
C=nan(numel(A),1)
for k=find(ismember(A,B(:,1))==1)
C(k)=B(find(B(:,1)==A(k)),2)
end
3 Comments
Matt Fig
on 25 Oct 2012
Give an example A and B that actually cover the type of data you will be encountering (this is what you should have done when you asked the first time!). Make sure your two example arrays cover all aspects of the real data...
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