Nested Loop not working

The error I am getting is Error using make_nextRow (line 21) Not enough input arguments. but i've rechecked the code and I can't see anything that is wrong

here is the code, and I commented what each line is supposed to to

 function rowfcn = make_nextRow(array, start_row)
  %
  % rowfcn = make_nextRow(array, start_row)
  % 
  % Returns a function handle, rowfcn.  When the function handle
  % is firet called, it will return the row defined by start_row.
  % Every call afterwards will return the next row below.
  %
  % If there are no more rows to return, an empty array, [], is returned.
  %
  % Inputs:
  %   array - A numerical MxN array 
  %   start_row - An index (integer) that indicates 
  %               which row to start returning values from
  %
  % Outputs:
  %   rowfcn - A handle to nextRow, which when alle
  %

M = start_row;
rowfcn = @nextRow; %Return a handle to the NESTED function, nextRow()

end

      function row = nextRow()

          % Check if M is within size(array) and if it is greater than 0
          if M <= array(size) && M > 0
              row = array(M,:);  % Get the M'th row from array and assign to row

              M= M+ 1;             % Increment M
          else
              row = [];
          end

      end

*this is the test case I used: *

scores = [20,90;13,56;3,67;10,78;2,54]

next_score = make_nextRow(scores,1)

next_score()

next_score()

next_score = make_nextRow(scores,4)

next_score()

next_score()

next_score()

these are the answers i'm supposed to get for my test case:

>> scores = [20,90;13,56;3,67; 10,78;2,54]

>>scores=

20 90 13 56 3 67 10 78 2 54

>> next_score = make_nextRow(scores,1)

next_score =

        @make_nextRow/nextRow

>> next_score()

ans = 20 90

>> next_score()

ans = 13 56

>> next_score = make_nextRow(e7_scores,4)

 next_score =

        @make_nextRow/nextRow

>> next_score()

ans = 10 78

>> next_score()

ans = 2 54

>> next_score()

ans = []

Answer 1

[per isakson]

Problems with your code:

• nextRow() is not properly defined as a nested function but rather as a subfunction. As a consequence the input arguments, array and start_row, are "lost".
• IMO: "M" is not an appropriate name for a row number.
• "array(size)" should be "size( array, 1 )"
• "nested loop" in the title is misleading

Your comments and programming style is good

I've modified the code (see below) and run

    scores = [20,90;13,56;3,67;10,78;2,54];
    next_score = make_nextRow( scores, 1 )
    next_score()
    next_score()

which returns

    next_score = 
        @make_nextRow/nextRow
    ans =
        20    90
    ans =
        13    56
    >>

where

    function rowfcn = make_nextRow( array, start_row )
    M = start_row;
    rowfcn = @nextRow; %Return a handle to the NESTED function, nextRow()

        function row = nextRow()
            if M <= size( array, 1 ) && M > 0
                row = array( M, : ); 
                M= M+ 1;             
            else
                row = [];
            end
        end
    end

.

I don't know if that is the expected result. I let you check that.

[Ping]

but the first part is just the test case so I can't edit that. I edited the question to make it clearer

[per isakson]

I don't understand!

I have:

1. fixed a few problems in your function, make_nextRow
2. deleted blank lines and comments to keep the answer compact
3. demonstrated that it returns numbers, which you have confirmed are indeed those expected.

What more do you expect?

Answer 2

[Matt J]

At the command line, execute

 which -all make_nextRow

and see if it reports any other versions of make_nextRow existing on your path.