How to stop the program if an array is empty?
4 views (last 30 days)
Show older comments
signal1 = [1,2,3,4,5,6];
signal2 = [7,8,9,10,11,12];
signal3 = [13,14,15,16,17,18];
signal4 = [19,20,21,22,23,24];
signal5 = [25,26,27,28,29,30];
signal6 = [31,32,33,34,35,36];
bufferSize = 6;
buffer = nan(bufferSize,6);
init = 1;
for i = 1:bufferSize
empty = sum(isnan(buffer(i,:))); %check status of each row
if empty == 6
buffer(i,1) = signal1(init);
buffer(i,2) = signal2(init);
buffer(i,3) = signal3(init);
buffer(i,4) = signal4(init);
buffer(i,5) = signal5(init);
buffer(i,6) = signal6(init);
init = init + 1; %infite number of data as input
if sum(isnan(signal1(1,init))) > 0
msgbox('Insufficient data')
break;
end
end
end
I have 6 signals of same size and I take the first value of each one of them and save them in the fist row of my buffer. However, when I change the bufferSize to 7 I have the following error:
Index exceeds matrix dimensions:
Error in test_array (line 28)
buffer(i,1) = signal1(init);
Its because the signal doesnt have enough data to fill the buffer.
I thought that by checking if the signal is expecting a new value before loading would stop the program before the warning, but it didnt worked.
if sum(isnan(signal1(1,init))) > 0
msgbox('Insufficient data')
break;
end
0 Comments
Accepted Answer
Ajay Kumar
on 11 Feb 2020
Edited: Ajay Kumar
on 11 Feb 2020
Handle the exception using try catch blocks
signal1 = [1,2,3,4,5,6];
signal2 = [7,8,9,10,11,12];
signal3 = [13,14,15,16,17,18];
signal4 = [19,20,21,22,23,24];
signal5 = [25,26,27,28,29,30];
signal6 = [31,32,33,34,35,36];
bufferSize = 6;
buffer = nan(bufferSize,6);
init = 1;
for i = 1:bufferSize
empty = sum(isnan(buffer(i,:))); %check status of each row
if empty == 6
buffer(i,1) = signal1(init);
buffer(i,2) = signal2(init);
buffer(i,3) = signal3(init);
buffer(i,4) = signal4(init);
buffer(i,5) = signal5(init);
buffer(i,6) = signal6(init);
init = init + 1; %infite number of data as input
try
signal1(1,init);
catch
msgbox(['Insufficient data at position ',num2str(init)])
break;
end
end
end
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!