Why Matlab Function block don't perform operations in matrix of different size? (Matlab2019a)
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Rubem Pacelli
on 30 Jan 2020
Commented: Rubem Pacelli
on 31 Jan 2020
In Workspace, if a you have a matrix A of size [8 5] and a matrix B of size [1 5], you could perform the following operation:
A-B
the row in B will be used for each line on A. But Matlab Function block doesn't able to perform this operation. You will recieve this error:
Size mismatch (size [8 x 5] ~= size [1 x 5])
What is the problem with handling this in the Matlab function block?
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Accepted Answer
Walter Roberson
on 30 Jan 2020
MATLAB Function Blocks are processed by something similar to MATLAB Coder, and do not support full MATLAB. In particular, implicit expansion is not supported at this time. Try bsxfun(@minus, A, B)
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