ｚ＝ｘtanθを求めたい

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Ryosuke KIJIMA
Ryosuke KIJIMA on 27 Jan 2020
Answered: Ryosuke KIJIMA on 27 Jan 2020
θ＝３０°
ｘ＝６００
の時のｚを求める式を教えてください。

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Accepted Answer

Takumi
Takumi on 27 Jan 2020
Edited: Takumi on 27 Jan 2020
こんなかんじでしょうか．
theta = 30*pi/180;
x = 600;
z = x*tan(theta)

More Answers (1)

Ryosuke KIJIMA
Ryosuke KIJIMA on 27 Jan 2020
できました！ ありがとうございます！

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