Generate an array within three loops
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Answers (1)
David Hill
on 16 Jan 2020
count=1;
for n=.1:.1:.5
for m=.1:.1:.5
for k=1:5
c(count)=94*2.4^n*.4^m;%1^k is always 1, so it doesn't matter
count=count+1
end
end
end
2 Comments
David Hill
on 16 Jan 2020
count=1;
a=[94 2.4 .4 1];
for n=.1:.1:.5
for m=.1:.1:.5
for k=.1:.1:5
c(count)=A(1,1)*A(1,2)^n*A(1,3)^m*A(1,4)^k;
count=count+1
end
end
end
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