Creating an array from 1 to n
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Agnieszka Polak
on 20 Dec 2019
Commented: Hans Henning Erle
on 17 Nov 2021
Hello!
I am trying to create an array of integers from 1 to n [1 2 3 ..... n], where n is a variable that can change.
How should I approach that?
Thank you!
3 Comments
Luis Benitez Prieto
on 27 Jul 2021
It is elemantary but also not. If you look at the accepted answer below. The answer is creating a double array, the numbers inside are integer values, but not of interger format.
I actually was interested in this question because when I want to create an array of integers I do not want to create a double array in the process by doing something like:
uint32([1:10])
Instead, I would like to directly create an integer array. And thats something I have not easily found in the documentation and a legit question in my opinion. Perhaps thats what the poster is asking for.
Stephen23
on 27 Jul 2021
Edited: Stephen23
on 27 Jul 2021
@Luis Benitez Prieto: like this:
V = uint32(1):uint32(10)
class(V)
Note that just one uint32 input is sufficient to define the output as uint32:
class(uint32(1):10)
class(1:uint32(10))
Note that the square brackets in your example are superfluous and misleading:
Accepted Answer
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