Finding max value and its position in ed matrix

Hello,

I know this question has alreayd been asked a million times, yet I have not managed to solve it by looking at previous documentation.

I have a 3d matrix. I want to find the max value in each "page" (max of 1st and 2nd dimension) along the third dimension. And I also want to know the indeces of the value.

Here is my attempt at the code.

C is my 3d matrix i want to get the max values from.

Cmax = zeros(1,numkx);
row = zeros(1,numkx);
column = zeros(1,numkx);

for c = 1 : numkx
    Cpage(:,:,c)= C(:,:,c);
    Cmax(:,:,c) = max(Cpage(:));
    [row,column] = find(Cpage(:) == Cmax(1,c));
end

Answer 1

[Andrei Bobrov]

[m,~,k] = size(C);
[C_max_of_page,i] = max(reshape(C,[],k));
index_of_C_max_of_page = [mod(i-1,m)+1; ceil(i/m); (1:k)];

[Lucrezia Cester]

This seems to give the max values in a increasing order. It basically tells me 1 at position row = x, column = y, then 2 is at position....etc.

I wanted to know the max value of each page of the 3d matrix instead.

[Andrei Bobrov]

I'm fixed answer.

>> C = randi(120,3,3,3)
C(:,:,1) =
    19    46    58
   103    23    15
    78    52    71
C(:,:,2) =
    28    31    32
    47    35    99
    70    75   118
C(:,:,3) =
    88    13    99
    42   109    32
    71   106    72
>> [m,~,k] = size(C);
[C_max_of_page,i] = max(reshape(C,[],k))
index_of_C_max_of_page = [mod(i-1,m)+1; ceil(i/m); (1:k)]
C_max_of_page =
   103   118   109
i =
     2     9     5
index_of_C_max_of_page =
     2     3     2
     1     3     2
     1     2     3
>>