Replacing the last value after consecutive Nan

Hello everyone,

I would like to know how to replace a stand alone value that's greater than zero and follows a row of Nans. I would eventually replace that value with a 0.

For example, A = [ 0 0 0 Nan Nan Nan 1.2 0 0 Nan Nan 2.3 1 2 5], as you can see in A the value that I would want to replace by 0 is 1.2, I would like it to A = [ 0 0 0 Nan Nan Nan 0 0 0 Nan Nan 2.3 1 2 5]. I'm not sure how to approach this. Do I try to find the indices of the non nan values? and if I do that what would be next.

Help would be much appreciated.

Thank you in advance!

[Bhaskar R]

What about the value 2.3 after NaN ? Should it need to be 0?

[M]

Do you want to replace the value after 3 consecutive NaN or after any NaN values ?

In any case, you can start by looking at the isnan function.

[John Doe]

No, since it isn't a stand alone value, I want to keep it as it is along with the values that follow it. By stand alone I mean the only value that's greater than zero, following a Nan

Answer 1

[Stijn Haenen]

Try this:

for i=2:numel(A)
    if isnan(A(i-1))&&A(i)>0
        A(i)=0;
    end
end

[John Doe]

Thank you!

It works perfectly!