How to cut dimensions of 3d arrays in a cell.

I have one 34*1 cell.

every array in it have 3 dimensions, all same (720*360*365)

I want to know how to cut all arrays like this: (700:720 * 300:360 * :)

Answer 1

[Yuan Li]

B = cell(34,1);
for ii = 1:34
   B{ii} = precips{ii}(700:720,300:360,:); 
end

Then you will get a new cell, each element of the new cell is of size 21*61*365.

[BN]

Special thank to both answer

Answer 2

[Alex Mcaulley]

Being A your cell array:

newA = arrayfun(@(i) A{i}(700:720,300:360,:),1:numel(A),'uni',0)

[BN]

Thank you it's work, but it looks like transpose or something because if you look at the picture before using code all arrays are in a column but after using code all appear in row number 1 and different column. can you help me fix this problem and all arrays store in 1 column (just like firs picture in question)?

thank you

[Alex Mcaulley]

Then, you can transpose the cell array:

newA = arrayfun(@(i) A{i}(700:720,300:360,:),1:numel(A),'uni',0)'